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树的非递归遍历 粗糙版【转】
转自：http://www.blogjava.net/javacap/archive/2007/10/11/152073.html
/**
 * 
 */

import java.util.Stack;
import java.util.Vector;

/**
 * @author yovn
 *
 */
public class TreeDemo {
    
    static interface NodeVistor
    {
         <T> void visit(BinaryTreeNode<T> node);
    }
    static class BinaryTree<T>
    {
        BinaryTreeNode<T> root;
        
        public BinaryTree(BinaryTreeNode<T> root) {
            this.root=root;
        }

        //no recursion ,pre-order
        void NLRVisit(NodeVistor visitor)
        {
            BinaryTreeNode<T> pointer=root;
            Stack<BinaryTreeNode<T>> stack=new Stack<BinaryTreeNode<T>>();
            while(!stack.isEmpty()||pointer!=null)
            {
                if(pointer!=null)
                {
                    visitor.visit(pointer);
                    if(pointer.rightChild!=null)
                    {
                        stack.push(pointer.rightChild);
                    }
                    pointer=pointer.leftChild;
                }
                //go to right child
                else
                {
                    pointer=stack.pop();
                    
                }
            }
        }
        
        //no recursion , in-order
        void LNRVisit(NodeVistor visitor)
        {
            BinaryTreeNode<T> pointer=root;
            Stack<BinaryTreeNode<T>> stack=new Stack<BinaryTreeNode<T>>();
            while(!stack.isEmpty()||pointer!=null)
            {
                if(pointer!=null)
                {
                    stack.push(pointer);
                    
                    pointer=pointer.leftChild;
                }
                //no left child here, then visit root and then go to right child
                else
                {
                    pointer=stack.pop();
                    visitor.visit(pointer);
                    pointer=pointer.rightChild;
                    
                }
            }
        }
        
        
        //no recursion ,post-order,this one is the most complex one.
        //we need know from which side ,it back(left or right)
        void LRNVisit(NodeVistor visitor)
        {
            if(root==null)return;
            BinaryTreeNode<T> pointer=root;
            Stack<BinaryTreeNode<T>> stack=new Stack<BinaryTreeNode<T>>();
            while(true)
            {
                
                //mark left 
                while(pointer!=null)
                {
                    stack.push(pointer);
                    pointer=pointer.leftChild;
                }
                
                
                pointer=stack.pop();
                
                while(pointer.visitedRight)//back from right child, so we can visit it now.
                {
                    visitor.visit(pointer);
                    if(stack.isEmpty())return;
                    pointer=stack.pop();
                }
            
                pointer.visitedRight=true;
                stack.push(pointer);
                
                pointer=pointer.rightChild;
                
                
            }
            
        }
        
        
        void levelOrder(NodeVistor visitor)
        {
            if(root==null)return;
            BinaryTreeNode<T> pointer=root;
            Vector<BinaryTreeNode<T>> queue=new Vector<BinaryTreeNode<T>>();
            
            queue.add(pointer);
            while(!queue.isEmpty())
            {
                BinaryTreeNode<T> node=queue.remove(0);
                visitor.visit(node);
                if(node.leftChild!=null)
                {
                    queue.add(node.leftChild);
                }
                if(node.rightChild!=null)
                {
                    queue.add(node.rightChild);
                }
                
            }
            
        }
        
    }
    static class BinaryTreeNode<T>
    {
        
        BinaryTreeNode(T data)
        {
            this.data=data;
        }
        T data;
        boolean visitedRight;
        BinaryTreeNode<T> leftChild;
        BinaryTreeNode<T> rightChild;
    }

    /**
     * 
     */
    public TreeDemo() {
        // TODO Auto-generated constructor stub
    }

    /**
     * @param args
     */
    public static void main(String[] args) {
        BinaryTreeNode<String> root=new BinaryTreeNode<String>("A");
        root.leftChild=new BinaryTreeNode<String>("B");
        root.rightChild=new BinaryTreeNode<String>("C");
        
        
        root.leftChild.leftChild=new BinaryTreeNode<String>("D");
        
        root.rightChild.leftChild=new BinaryTreeNode<String>("E");
        
        root.rightChild.rightChild=new BinaryTreeNode<String>("F");
        
        root.rightChild.leftChild.rightChild=new BinaryTreeNode<String>("G");
        
        root.rightChild.rightChild.leftChild=new BinaryTreeNode<String>("H");
        root.rightChild.rightChild.rightChild=new BinaryTreeNode<String>("I");
        
        NodeVistor visitor=new NodeVistor()
        {

            @Override
            public <T> void visit(BinaryTreeNode<T> node) {
                System.out.print("'"+node.data+"'");
                
            }
            
        };
        
        BinaryTree<String> tree=new BinaryTree<String>(root);

        
        System.out.println("pre-order visit");
        tree.NLRVisit(visitor);
        System.out.println();
        System.out.println("in-order visit");
        
        tree.LNRVisit(visitor);
        
        System.out.println();
        System.out.println("post-order visit");
        
        tree.LRNVisit(visitor);
        
        System.out.println();
        System.out.println("level-order visit");
        
        tree.levelOrder(visitor);
    }

}

posted on 2009-04-15 22:03 weesun一米阳光 阅读(242) 评论(0)  编辑  收藏 所属分类: JAVA源码 、总结备用

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