Oracle中INSTR和SUBSTR的用法 (2009-09-18 13:17:08)转载▼ 标签： substr instr it 分类： 技术文章
Oracle中INSTR和SUBSTR的用法
Oracle中INSTR的用法：
INSTR方法的格式为
INSTR(源字符串, 要查找的字符串, 从第几个字符开始, 要找到第几个匹配的序号)
返回找到的位置，如果找不到则返回0.
例如：INSTR('CORPORATE FLOOR','OR', 3, 2)中，源字符串为'CORPORATE FLOOR', 在字符串中查找'OR'，从第三个字符位置开始查找"OR"，取第三个字后第2个匹配项的位置。
默认查找顺序为从左到右。当起始位置为负数的时候，从右边开始查找。
所以SELECT INSTR('CORPORATE FLOOR', 'OR', -1, 1) "aaa" FROM DUAL的显示结果是
Instring
——————
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oracle的substr函数的用法：
取得字符串中指定起始位置和长度的字符串 substr( string, start_position, [ length ] )
如:
substr('This is a test', 6, 2) would return 'is'
substr('This is a test', 6) would return 'is a test'
substr('TechOnTheNet', -3, 3) would return 'Net'
substr('TechOnTheNet', -6, 3) would return 'The'
select substr('Thisisatest', -4, 2) value from dual
综合应用：
SELECT INSTR('CORPORATE FLOOR', 'OR', -1, 1) "Instring" FROM DUAL
--INSTR(源字符串, 目标字符串, 起始位置, 匹配序号)
SELECT INSTR('CORPORATE FLOOR','OR', 3, 2) "Instring" FROM DUAL
SELECT INSTR('32.8,63.5',',', 1, 1) "Instring" FROM DUAL
SELECT SUBSTR('32.8,63.5',INSTR('32.8,63.5',',', 1, 1)+1) "INSTRING" FROM DUAL
SELECT SUBSTR('32.8,63.5',1,INSTR('32.8,63.5',',', 1, 1)-1) "INSTRING" FROM DUAL
-- CREATED ON 2008-9-26 BY ADMINISTRATOR
DECLARE
-- LOCAL VARIABLES HERE
T VARCHAR2(2000);
S VARCHAR2(2000);
NUM INTEGER;
I INTEGER;
POS INTEGER;
BEGIN
-- TEST STATEMENTS HERE
T := '12.3,23.0;45.6,54.2;32.8,63.5;';
SELECT LENGTH(T) - LENGTH(REPLACE(T, ';', '')) INTO NUM FROM DUAL;
DBMS_OUTPUT.PUT_LINE('NUM:' || NUM);
POS := 0;
FOR I IN 1 .. NUM LOOP
DBMS_OUTPUT.PUT_LINE('I:' || I);
DBMS_OUTPUT.PUT_LINE('POS:' || POS);
DBMS_OUTPUT.PUT_LINE('==:' || INSTR(T, ';', 1, I));
DBMS_OUTPUT.PUT_LINE('INSTR:' || SUBSTR(T, POS + 1, INSTR(T, ';', 1, I) - 1));
POS := INSTR(T, ';', 1, I);
END LOOP;
END;
-- Created on 2008-9-26 by ADMINISTRATOR
declare
-- Local variables here
i integer;
T VARCHAR2(2000);
S VARCHAR2(2000);
begin
-- Test statements here
--历史状态
T := '12.3,23.0;45.6,54.2;32.8,63.5;';
IF (T IS NOT NULL) AND (LENGTH(T) > 0) THEN
--T := T || ',';
WHILE LENGTH(T) > 0 LOOP
--ISTATUSID := 0;
S := TRIM(SUBSTR(T, 1, INSTR(T, ';') - 1));
IF LENGTH(S) > 0 THEN
DBMS_OUTPUT.PUT_LINE('LAT:'||SUBSTR('32.8,63.5',1,INSTR('32.8,63.5',',', 1, 1)-1));
DBMS_OUTPUT.PUT_LINE('LON:'||SUBSTR('32.8,63.5',INSTR('32.8,63.5',',', 1, 1)+1));
-- COMMIT;
END IF;
T := SUBSTR(T, INSTR(T, ';') + 1);
END LOOP;
END IF;
end;