Posted on 2009-10-30 14:20
Robin 阅读(326)
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Queue实现的是点到点模型,在下面的例子中,启动2个消费者共同监听一个Queue,然后循环给这个Queue中发送多个消息,我们依然采用ActiveMQ。
import javax.jms.Connection;
import javax.jms.DeliveryMode;
import javax.jms.JMSException;
import javax.jms.Message;
import javax.jms.MessageConsumer;
import javax.jms.MessageListener;
import javax.jms.MessageProducer;
import javax.jms.Queue;
import javax.jms.Session;
import javax.jms.TextMessage;
import org.apache.activemq.ActiveMQConnectionFactory;
import org.apache.activemq.command.ActiveMQQueue;
public class QueueTest {
public static void main(String[] args) throws Exception {
ActiveMQConnectionFactory factory = new ActiveMQConnectionFactory("vm://localhost");
Connection connection = factory.createConnection();
connection.start();
//创建一个Queue
Queue queue = new ActiveMQQueue("testQueue");
//创建一个Session
Session session = connection.createSession(false, Session.AUTO_ACKNOWLEDGE);
//注册消费者1
MessageConsumer comsumer1 = session.createConsumer(queue);
comsumer1.setMessageListener(new MessageListener(){
public void onMessage(Message m) {
try {
System.out.println("Consumer1 get " + ((TextMessage)m).getText());
} catch (JMSException e) {
e.printStackTrace();
}
}
});
//注册消费者2
MessageConsumer comsumer2 = session.createConsumer(queue);
comsumer2.setMessageListener(new MessageListener(){
public void onMessage(Message m) {
try {
System.out.println("Consumer2 get " + ((TextMessage)m).getText());
} catch (JMSException e) {
e.printStackTrace();
}
}
});
//创建一个生产者,然后发送多个消息。
MessageProducer producer = session.createProducer(queue);
for(int i=0; i<10; i++){
producer.send(session.createTextMessage("Message:" + i));
}
}
}
运行这个例子会得到下面的输出结果:
Consumer1 get Message:0
Consumer2 get Message:1
Consumer1 get Message:2
Consumer2 get Message:3
Consumer1 get Message:4
Consumer2 get Message:5
Consumer1 get Message:6
Consumer2 get Message:7
Consumer1 get Message:8
Consumer2 get Message:9
可以看出每个消息直被消费了一次,但是如果有多个消费者同时监听一个Queue的话,无法确定一个消息最终会被哪一个消费者消费。