1.在一些字符串数组中，常会有重复的记录，比如手机号码，我们可以通过Hashtable来对其进行过滤public String[] checkArray(String[] str)...{ Hashtable<String, String> hash=new Hashtable<String, String>(); for(int i=0;i<str.length;i++)...{ if(!hash.containsKey(str[i])) hash.put(str[i], str[i]); } Enumeration enumeration=hash.keys(); String[] str_new=new String[hash.size()]; int i=0; while(enumeration.hasMoreElements())...{ str_new[i]=enumeration.nextElement().toString(); i++; } return str_new; }示例： String[] mobile={"13811071500","13811071500","13811071501","13811071503","13811071501"}; mobile=checkArray(mobile); for(int i=0;i<mobile.length;i++) System.out.println(mobile[i]); 输出结果为： 13811071503 13811071501 138110715002.A,B均为字符串数组，找出在A中存在，而在B中不存在的字符串 public String[] compareArray(String[] A,String[] B){ Hashtable<String, String> hash=new Hashtable<String, String>(); Hashtable<String, String> hash_new=new Hashtable<String, String>(); for(int i=0;i<B.length;i++) hash.put(B[i], B[i]); for(int i=0;i<A.length;i++){ if(!hash.containsKey(A[i])) hash_new.put(A[i], A[i]); } String[] C=new String[hash_new.size()]; int i=0; Enumeration enumeration=hash_new.keys(); while(enumeration.hasMoreElements()){ C[i]=enumeration.nextElement().toString(); i++; } return C; }示例： String[] mobile1={"13811071500","13811071501","13811071502","13811071503","13811071504"}; String[] mobile2={"13811071500","13811071505","13811071502","13811071506","13811071504"}; String[] mobile3=compareArray(mobile1,mobile2); for(int i=0;i<mobile3.length;i++) System.out.println(mobile[i]);输出结果： 13811071503 13811071501存在的问题：每次都是倒序，可以再对程序稍加改动，变成正序。3.将一个字符串数组中某一个特定的字符串过滤掉/** *//**检验一个字符串数组，若包含某一特定的字符串，则将该字符串从数组中删除，返回剩余的字符串数组 * @param str_array 字符串数组 * @param str_remove 待删除的字符串 * @return 过滤后的字符串 */ public String[] removeStrFromArray(String[] str_array,Stringstr_remove)...{ Hashtable<String, String> hash=new Hashtable<String, String>(); for(int i=0;i<str_array.length;i++)...{ if(!str_array[i].equals(str_remove)) hash.put(str_array[i], str_array[i]); } //生成一个新的数组 String[] str_new=new String[hash.size()]; int i=0; Enumeration enumeration=hash.keys(); while(enumeration.hasMoreElements())...{ str_new[i]=enumeration.nextElement().toString(); i++; } return str_new; }
posted on 2007-11-06 21:07
jadmin 阅读(93)
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