Posted on 2008-10-04 19:50
Qzi 阅读(1043)
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java foundation
Pattern类:
例子:
Pattern pattern = Pattern.compile("[,\\s]+");
String[] result = pattern.split("one two three,four,five, six");
for(int i = 0; i<result.length; i++){
System.out.println(result[i]);
}
输出结果是:
one
two
three
four
five
six
Pattern类的静态方法compile用来编译正则表达式,在此[,\\s]+表示若干个","或者若干个空格匹配
split方法使用正则匹配将字符串切割成各子串并且返回
Matcher类:
注意,Matcher的获得是通过Pattern.matcher(CharSequence charSequence);输入必须是实现了CharSequence接口的类
常用方法:
matches()判断整个输入串是否匹配,整个匹配则返回true
例如下面会输出true
String str1 = "hello";
Pattern pattern1 = Pattern.compile("hello");
Matcher matcher1 = pattern1.matcher(str1);
System.out.println(matcher1.matches());
lookingAt()从头开始寻找,找到匹配则返回true
例如下面会输出true
String str2 = "hello yangfan!";
Pattern pattern2 = Pattern.compile("hello");
Matcher matcher2 = pattern2.matcher(str2);
System.out.println(matcher2.lookingAt());
find()扫描输入串,寻找下一个匹配子串,存在则返回true
例如下面将会将所有no替换成yes
Pattern pattern = Pattern.compile("no");
Matcher matcher = pattern.matcher("Does jianyue love yangfan? no;" +
"Does jianyue love yangfan? no;Does jianyue love yangfan? no;");
StringBuffer sb = new StringBuffer();
boolean find = matcher.find();
while(find){
matcher.appendReplacement(sb, "yes");
find = matcher.find();
}
matcher.appendTail(sb);
System.out.println(sb.toString());