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public class Jtest
{
int m=1;
int i=3;
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void Jtest()
{
m=2;
i=4;
}
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public static void main(String[] args)
{
Jtest app=new Jtest();
System.out.println(app.m+","+app.i);
}
}
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写出输出.
结果是1,3;
因为在这里void Jtest();并没有并调用,它只是一个
方法,而非构造方法,这样的编写是有警告的,不过
可以运行.
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public class Jtest
{
int m=1;
int i=3;
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Jtest()
{
m=2;
i=4;
}
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public static void main(String[] args)
{
Jtest app=new Jtest();
System.out.println(app.m+","+app.i);
}
}
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写出输出:
结果是2,4;
调用了构造方法,不加修饰符,默认访问权限是
package access,在Java里没有关键字表示,就是
包内的能访问,包外就不行了(即使导入也不行).
public class Test
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{
static void oper(int b)
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{
b = b + 100;
}
public static void main(String[] args)
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{
int a = 99;
oper(a);
System.out.println(a);
}
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}
输出为99.
我们来分析一下内存:
int a = 99;
首先在栈里面开辟一块空间保存a
比如:a:xxxx
然后调用oper(a);
这时把a 的值99赋给int b;
b在内存里也开辟了自己的空间,此时
值也是99.
然后执行oper(a);方法体,b = b + 100;
此时b的值为199,a的值为99.
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public class Test
{
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public static void main(String[] args)
{
String a=new String("A");
String b=new String("B");
oper(a,b);
System.out.print(a+","+b);
}
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static void oper(String c,String d)
{
c.concat("B");
d=c;
}
}
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此程序输出:A和B.
原因就是String是final类型的.并不会被改变.
public class Test
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{
public static void main(String[] args)
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{
String a = new String("A");
String b = new String("B");
a.concat("aa");
System.out.println(a + "," + b);
}
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}
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这个还是会输出A,B
原因同上.
package intervie;
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public class Test
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{
public static void main(String[] args)
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{
String a = new String("A");
String b = new String("B");
a = a.concat("aa");
System.out.println(a + "," + b);
}
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}
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做了下改动,再来看看.结果就不同了.
输出的是Aaa,B
因为String 是final类型的.所以执行到
a = c.concat("aa");
会在heap里新创建一个对象,而a指向它.
这是一新的地址,同String a 这个已经不同了.
所以输出的是后一个.即改变后的值.
public class Test
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{
static void oper(StringBuffer c,StringBuffer d)
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{
d = c.append("B");
}
public static void main(String[] args)
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{
StringBuffer a = new StringBuffer("A");
StringBuffer b = new StringBuffer("B");
oper(a, b);
System.out.println(a + "," + b);
}
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}
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此程序会输出:AB,B
StringBuffer是可变的线程安全的.
原试题下载地址:点此下载