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方法一: Java代码 - public void saveIcon(Bitmap icon) {
- if (icon == null) {
- return;
- }
-
- // 最终图标要保存到浏览器的内部数据库中,系统程序均保存为SQLite格式,Browser也不例外,因为图片是二进制的所以使用字节数组存储数据库的
- // BLOB类型
- final ByteArrayOutputStream os = new ByteArrayOutputStream();
- // 将Bitmap压缩成PNG编码,质量为100%存储
- icon.compress(Bitmap.CompressFormat.PNG, 100, os);
- // 构造SQLite的Content对象,这里也可以使用raw
- ContentValues values = new ContentValues();
- // 写入数据库的Browser.BookmarkColumns.TOUCH_ICON字段
- values.put(Browser.BookmarkColumns.TOUCH_ICON, os.toByteArray());
-
- DBUtil.update(....);//调用更新或者插入到数据库的方法
- }
方法二:如果数据表入口时一个content:URI Java代码 - import android.provider.MediaStore.Images.Media;
- import android.content.ContentValues;
- import java.io.OutputStream;
-
- // Save the name and description of an image in a ContentValues map.
- ContentValues values = new ContentValues(3);
- values.put(Media.DISPLAY_NAME, "road_trip_1");
- values.put(Media.DESCRIPTION, "Day 1, trip to Los Angeles");
- values.put(Media.MIME_TYPE, "image/jpeg");
-
- // Add a new record without the bitmap, but with the values just set.
- // insert() returns the URI of the new record.
- Uri uri = getContentResolver().insert(Media.EXTERNAL_CONTENT_URI, values);
-
- // Now get a handle to the file for that record, and save the data into it.
- // Here, sourceBitmap is a Bitmap object representing the file to save to the database.
- try {
- OutputStream outStream = getContentResolver().openOutputStream(uri);
- sourceBitmap.compress(Bitmap.CompressFormat.JPEG, 50, outStream);
- outStream.close();
- } catch (Exception e) {
- Log.e(TAG, "exception while writing image", e);
- }
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