检查字符串是否为空或null或仅仅包含空格
String test = "";
String test1=" ";
String test2 = "\n\n\t";
String test3 = null;
System.out.println( "test blank? " + StringUtils.isBlank( test ) );
System.out.println( "test1 blank? " + StringUtils.isBlank( test1 ) );
System.out.println( "test2 blank? " + StringUtils.isBlank( test2 ) );
System.out.println( "test3 blank? " + StringUtils.isBlank( test3 ) );
运行结果:
test blank? true
test1 blank? true
test2 blank? true
test3 blank? true
相对应的还有一个StringUtils.isNotBlank(String str)
StringUtils.isEmpty(String str)则检查字符串是否为空或null(不检查是否仅仅包含空格)
分解字符串
StringUtils.split(null, *, *) = null
StringUtils.split("", *, *) = []
StringUtils.split("ab de fg", null, 0) = ["ab", "cd", "ef"]
StringUtils.split("ab de fg", null, 0) = ["ab", "cd", "ef"]
StringUtils.split("ab:cd:ef", ":", 0) = ["ab", "cd", "ef"]
StringUtils.split("ab:cd:ef", ":", 1) = ["ab:cd:ef"]
StringUtils.split("ab:cd:ef", ":", 2) = ["ab", "cd:ef"]
StringUtils.split(String str,String separatorChars,int max) str为null时返回null
separatorChars为null时默认为按空格分解,max为0或负数时分解没有限制,max为1时返回整个字符串,max为分解成的个数(大于实际则无效)
去除字符串前后指定的字符
StringUtils.strip(null, *) = null
StringUtils.strip("", *) = ""
StringUtils.strip("abc", null) = "abc"
StringUtils.strip(" abc ", null) = "abc"
StringUtils.strip(" abcyx", "xyz") = " abc"
StringUtils.strip(String str,String stripChars) str为null时返回null,stripChars为null时默认为空格
创建醒目的Header(调试时用)
public String createHeader( String title ) {
int width = 30;
String stars = StringUtils.repeat( "*", width);
String centered = StringUtils.center( title, width, "*" );
String heading = StringUtils.join(new Object[]{stars, centered, stars}, "\n");
return heading;
}
调用createHeader("TEST")的输出结果:
******************************
************ TEST ************
******************************
字符的全部反转及以单个词为单位的反转
String original = "In time, I grew tired of his babbling nonsense.";
StringUtils.reverse( original ) = ".esnesnon gnilbbab sih fo derit werg I ,emit nI"
以单个词为单位的反转
public Sentence reverseSentence(String sentence) {
String reversed = StringUtils.chomp( sentence, "." );
reversed = StringUtils.reverseDelimited( reversed, ' ' );
reversed = reversed + ".";
return reversed;
}
String sentence = "I am Susan."
reverseSentence( sentence ) ) = "Susan am I."
检查字符串是否仅仅包含数字、字母或数字和字母的混合
String test1 = "ORANGE";
String test2 = "ICE9";
String test3 = "ICE CREAM";
String test4 = "820B Judson Avenue";
String test5 = "1976";
结果:
boolean t1val = StringUtils.isAlpha( test1 ); // returns true
boolean t2val = StringUtils.isAlphanumeric( test2 ); // returns true
boolean t3val = StringUtils.isAlphaSpace( test3 ); // returns true
boolean t4val = StringUtils.isAlphanumericSpace( test4 ); // returns true
boolean t5val = StringUtils.isNumeric( test5 ); // returns true
http://www.blogjava.net/ronghao 荣浩原创,转载请注明出处:)
posted on 2005-12-14 12:47
ronghao 阅读(2584)
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j2se基础