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package expression;
public class Calculate{
 public static boolean isOperator(String operator){
  if(operator.equals("+")||operator.equals("-")||operator.equals("*")||operator.equals("/")||operator.equals("(")||operator.equals(")")) return true;
  else return false;
 }
 public static int priority(String operator){
  if(operator.equals("+")||operator.equals("-")||operator.equals("(")) return 1;
  else if(operator.equals("*")||operator.equals("/")) return 2;
  else return 0;
 }
 public static String twoResult(String operator,String a,String b){
  try{
   String op=operator;
   String rs=new String();
   double x=Double.parseDouble(b);
   double y=Double.parseDouble(a);
   double z=0;
   if(op.equals("+")) z=x+y;
   else if(op.equals("-")) z=x-y;
   else if(op.equals("*")) z=x*y;
   else if(op.equals("/")) z=x/y;
   else z=0;
   return rs+z;
  }
  catch(NumberFormatException e){
   System.out.println("input has something wrong!");
   return "Error";
  }
 }
}

 

 

package expression;
import java.util.*;
public class Stacks{
 private LinkedList list=new LinkedList();
 int top=-1;
 public void push(Object value){
  top++;
  list.addFirst(value);
 }
 public Object pop(){
  Object temp=list.getFirst();
  top--;
  list.removeFirst();
  return temp;

 }
 public Object top(){
  return list.getFirst();
 }
}

 

package expression;
import java.io.*;
import java.util.*;
public class Expression{
 private ArrayList expression=new ArrayList();//存储中序表达式
 private ArrayList right=new ArrayList();//存储右序表达式
 private String result;//结果
 //依据输入信息创建对象,将数值与操作符放入ArrayList中
 private Expression(String input){
  StringTokenizer st=new StringTokenizer(input,"+-*/()",true);
  while(st.hasMoreElements()){
   expression.add(st.nextToken());
  }
 }
 //将中序表达式转换为右序表达式
 private void toRight(){
  Stacks aStack=new Stacks();
  String operator;
  int position=0;
  while(true){
   if(Calculate.isOperator((String)expression.get(position))){
    if(aStack.top==-1||((String)expression.get(position)).equals("(")){
     aStack.push(expression.get(position));
    }
    else{
     if(((String)expression.get(position)).equals(")")){
      if(!((String)aStack.top()).equals("(")){
       operator=(String)aStack.pop();
       right.add(operator);
      }
     }
     else{
      if(Calculate.priority((String)expression.get(position))<=Calculate.priority((String)aStack.top())&&aStack.top!=-1){
       operator=(String)aStack.pop();
       if(!operator.equals("(")) right.add(operator);
      }
      aStack.push(expression.get(position));
     }
    }
   }
   else right.add(expression.get(position));
   position++;
   if(position>=expression.size()) break;
  }
  while(aStack.top!=-1){
   operator=(String)aStack.pop();
   right.add(operator);
  }
 }
 //对右序表达式进行求值
 private void getResult(){
  this.toRight();
  Stacks aStack=new Stacks();
  String op1,op2,is=null;
  Iterator it=right.iterator();
  while(it.hasNext()){
   is=(String)it.next();
   if(Calculate.isOperator(is)){
    op1=(String)aStack.pop();
    op2=(String)aStack.pop();
    aStack.push(Calculate.twoResult(is,op1,op2));
   }
   else aStack.push(is);
  }
  result=(String)aStack.pop();
  it=expression.iterator();
  while(it.hasNext()){
   System.out.print((String)it.next());
  }
  System.out.println("="+result);
 }
 public static void main(String avg[]){
  try{
   System.out.println("Input a expression:");
   BufferedReader is=new BufferedReader(new InputStreamReader(System.in));
   for(;;){
    String input=new String();
    input=is.readLine().trim();
    if(input.equals("q")) break;
    else{
     Expression boya=new Expression(input);
     boya.getResult();
    }
    System.out.println("Input another expression or input 'q' to quit:");
   }
   is.close();
  }
  catch(IOException e){
   System.out.println("Wrong input!!!");
  }
 }
}

posted on 2005-07-27 11:45 Cavenaghi 阅读(1003) 评论(1)  编辑  收藏

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# re: 数据结构JAVA示例---逆波兰式求值! 2005-07-27 17:36 蘑菇
问个弱弱的问题:“逆波兰式求值”是啥米东西?  回复  更多评论
  


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