Like SQL语句的优化的一个小测试

1.尽量不要使用 like '%..%'

2.对于 like '..%..' (不以 % 开头)，Oracle可以应用 colunm上的index

3.对于 like '%...' 的 (不以 % 结尾)，可以利用reverse + function index 的形式，变化成 like '..%'

具体的测试流程： (测试工具：PLSQL Developer)

[1] '建测试表和Index，注意，重点在于带reverse的function index。同时，一定要使用CBO才行。

已连接到 Oracle Database 10g Enterprise Edition Release 10.2.0.1.0
已连接为 zxdbm_ismp

SQL> select reverse('123') from dual;

REVERSE('123')
--------------
321

SQL> create table test_like as select object_id,object_name from dba_objects;

Table created.

SQL> create index test_like_name on test_like(object_name);

Index created.

SQL> create index test_like_name_reverse on test_like(reverse(object_name));  --建反向索引

Index created.

SQL> analyze table test_like compute statistics for table for all indexes;

Table analyzed.

SQL> set autotrace trace exp

[2] '常量开头的like , 会利用index ，没问题…… '

SQL> select * from test_like where object_name like 'AS%';

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=2 Card=655 Bytes=15720)

1 0 TABLE ACCESS (BY INDEX ROWID) OF 'TEST_LIKE' (Cost=2 Card=655Bytes=15720)

2 1 INDEX (RANGE SCAN) OF 'TEST_LIKE__NAME' (NON-UNIQUE) (Cost=2 Card=118)

[3] '开头和结尾都是 % ,对不起，很难优化'

SQL> select * from test_like where object_name like '%%';

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=6 Card=655 Bytes=15720)

1 0 TABLE ACCESS (FULL) OF 'TEST_LIKE' (Cost=6 Card=655 ytes=15720)

[4] '以常量结束，直接写的时候是不能应用index的'

SQL> select * from test_like where object_name like '%S';

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=6 Card=655 Bytes=15720)

1 0 TABLE ACCESS (FULL) OF 'TEST_LIKE' (Cost=6 Card=655 Bytes=15720)

[5] '以常量结束的，加个reverse 函数，又可以用上index了'(需要反向索引的支持)

SQL> select * from test_like where reverse(object_name)like reverse('%AS');

Execution Plan

----------------------------------------------------------

0 SELECT STATEMENT Optimizer=CHOOSE (Cost=2 Card=655 Bytes=15720)

1 0 TABLE ACCESS (BY INDEX ROWID) OF 'TEST_LIKE' (Cost=2 Card=655 Bytes=15720)

2 1 INDEX (RANGE SCAN) OF 'TEST_LIKE__NAME_REVERSE' (NON-UNIQUE) (Cost=2 Card=118)