Problem Statement
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We have a sequence of integers, and we would like to remove all duplicate elements from this sequence. There may be multiple ways to perform this task. For example, given the sequence { 1, 2, 1, 3 }, we could end up with either { 1, 2, 3 } or { 2, 1, 3 } as the remaining sequence, depending on which duplicate 1 we remove from the original sequence. For this problem, we want to return the lexicographically first of of all possible remaining sequences. A sequence S1 comes before sequence S2 lexicographically if and only if S1 has a smaller value than S2 at the lowest index at which the two sequences differ (so, for example, { 1, 2, 3 } comes before { 2, 3, 1 }).
You will be given a int[] sequence. Return a int[] containing the sequence after all the duplicates are removed. See the examples for further clarification.
Definition
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Class:
HardDuplicateRemover
Method:
process
Parameters:
int[]
Returns:
int[]
Method signature:
int[] process(int[] sequence)
(be sure your method is public)
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Constraints
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sequence will have between 1 and 50 elements, inclusive.
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Each element of sequence will be between 1 and 1000, inclusive.
Examples
0)
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{5, 6, 5, 1, 6, 5}
Returns: {1, 6, 5 }
There are six different ways to remove duplicates (remaining numbers are marked by '*'):
{ *5, *6, 5, *1, 6, 5},
{ *5, 6, 5, *1, *6, 5},
{ 5, *6, *5, *1, 6, 5},
{ 5, 6, *5, *1, *6, 5},
{ 5, *6, 5, *1, 6, *5},
{ 5, 6, 5, *1, *6, *5}.
The last variant is the lexicographically first.
1)
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{3, 2, 4, 2, 4, 4}
Returns: {3, 2, 4 }
2)
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{6, 6, 6, 6, 6, 6}
Returns: {6 }
3)
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{1, 3, 2, 4, 2, 3}
Returns: {1, 2, 4, 3 }
4)
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{5, 4, 1, 5}
Returns: {4, 1, 5 }
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