随笔-167  评论-65  文章-0  trackbacks-0

1,rand(999999) 生成 6 位随机数

2,puts rand(0xffffff) # 十六进制的

3,puts rand 生成 0-1 之间的任意数

4,  def newpass( len )
chars = ("a".."z").to_a + ("A".."Z").to_a + ("0".."9").to_a
newpass = ""
1.upto(len) { |i| newpass << chars[rand(chars.size-1)] }
return newpass
end

puts   newpass(15)

ref:
http://snippets.dzone.com/posts/show/491
http://stackoverflow.com/questions/88311/how-best-to-generate-a-random-string-in-ruby



write by feng
posted on 2009-03-27 19:13 fl1429 阅读(8270) 评论(5)  编辑  收藏

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