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Posted on 2009-05-15 22:09 Gavin.lee 阅读(633) 评论(1) 编辑 收藏 所属分类: java SE & EE
摘 ： http://www.java2000.net/p32
 import java.math.BigDecimal;
  public class ConvertNumber  {
  /** *//** 定义数组存放数字对应的大写 */
private final static String[] STR_NUMBER = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };
/** *//** 定义数组存放位数的大写 */
private final static String[] STR_MODIFY = { "", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟" };
/** *//**
* 转化整数部分
*
* @param tempString
* @return 返回整数部分
 */
private static String getInteger(String tempString) {
/** *//** 用来保存整数部分数字串 */
String strInteger = null;//
/** *//** 记录"."所在位置 */
int intDotPos = tempString.indexOf(".");
int intSignPos = tempString.indexOf("-");
if (intDotPos == -1)
intDotPos = tempString.length();
/** *//** 取出整数部分 */
strInteger = tempString.substring(intSignPos + 1, intDotPos);
strInteger = new StringBuffer(strInteger).reverse().toString();
StringBuffer sbResult = new StringBuffer();
for (int i = 0; i < strInteger.length(); i++) {
sbResult.append(STR_MODIFY[i]);
sbResult.append(STR_NUMBER[strInteger.charAt(i) - 48]);
}
sbResult = sbResult.reverse();
replace(sbResult, "零拾", "零");
replace(sbResult, "零佰", "零");
replace(sbResult, "零仟", "零");
replace(sbResult, "零万", "万");
replace(sbResult, "零亿", "亿");
replace(sbResult, "零零", "零");
replace(sbResult, "零零零", "零");
/** *//** 这两句不能颠倒顺序 */
replace(sbResult, "零零零零万", "");
replace(sbResult, "零零零零", "");
/** *//** 这样读起来更习惯. */
replace(sbResult, "壹拾亿", "拾亿");
replace(sbResult, "壹拾万", "拾万");
/** *//** 删除个位上的零 */
if (sbResult.charAt(sbResult.length() - 1) == '零' && sbResult.length() != 1)
sbResult.deleteCharAt(sbResult.length() - 1);
if (strInteger.length() == 2) {
replace(sbResult, "壹拾", "拾");
}
/** *//** 将结果反转回来. */
return sbResult.toString();
}
/** *//**
* 转化小数部分 例：输入22.34返回叁肆
*
* @param tempString
* @return
*/
private static String getFraction(String tempString) {
String strFraction = null;
int intDotPos = tempString.indexOf(".");
/** *//** 没有点说明没有小数，直接返回 */
if (intDotPos == -1)
return "";
strFraction = tempString.substring(intDotPos + 1);
StringBuffer sbResult = new StringBuffer(strFraction.length());
for (int i = 0; i < strFraction.length(); i++) {
sbResult.append(STR_NUMBER[strFraction.charAt(i) - 48]);
}
return sbResult.toString();
}
/** *//**
* 判断传入的字符串中是否有.如果有则返回点
*
* @param tempString
* @return
*/
private static String getDot(String tempString) {
return tempString.indexOf(".") != -1 ? "点" : "";
}
/** *//**
* 判断传入的字符串中是否有-如果有则返回负
*
* @param tempString
* @return
*/
private static String getSign(String tempString) {
return tempString.indexOf("-") != -1 ? "负" : "";
}
/** *//**
* 将一个数字转化为金额
*
* @param tempNumber 传入一个double的变量
* @return 返一个转换好的字符串
*/
public static String numberToChinese(double tempNumber) {
java.text.DecimalFormat df = new java.text.DecimalFormat("#.#########");
String pTemp = String.valueOf(df.format(tempNumber));
StringBuffer sbResult = new StringBuffer(getSign(pTemp) + getInteger(pTemp) + getDot(pTemp) + getFraction(pTemp));
return sbResult.toString();
}
public static String numberToChinese(BigDecimal tempNumber) {
return numberToChinese(tempNumber.doubleValue());
}
/** *//**
* 替代字符
*
* @param pValue
* @param pSource
* @param pDest
*/
private static void replace(StringBuffer pValue, String pSource, String pDest) {
if (pValue == null || pSource == null || pDest == null)
return;
/** *//** 记录pSource在pValue中的位置 */
int intPos = 0;
do {
intPos = pValue.toString().indexOf(pSource);
/** *//** 没有找到pSource */
if (intPos == -1)
break;
pValue.delete(intPos, intPos + pSource.length());
pValue.insert(intPos, pDest);
} while (true);
}
/** *//**
* @param args
*/
public static void main(String[] args) {
System.out.println(numberToChinese(1230400567.8934));
}
 }
评论
# re: java 将数字金额转化为汉字（摘） 回复 更多评论
2012-09-19 15:34 by
好机会
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