需求:公司要将员工进行排序(不要说领导排在前面),我们的需求比较复杂。先进行姓排序,谁的姓拼音靠前,谁就排前面。然后对名字进行排序。恩.如果同名,女性排前头。如果名字和性别都相同,年龄小的排前头。
代码如下:
Person.java
package com.founder.common;
public class Person {
private String firstName;
private String lastName;
private boolean sex;
private int age;
public Person(String firstName, String lastName, boolean sex, int age) {
this.firstName = firstName;
this.lastName = lastName;
this.sex = sex;
this.age = age;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public boolean getSex() {
return sex;
}
public void setSex(boolean sex) {
this.sex = sex;
}
public String toString() {
return firstName + " " + lastName + " " + (sex ? "Male" : "Female") + " " + age;
}
}
Comparator.java
package com.founder.common;
public class Comparator{
public static Java.util.Comparator getComparator() {
return new Java.util.Comparator() {
public int compare(Object o1, Object o2) {
if (o1 instanceof String) {
return compare((String) o1, (String) o2);
} else if (o1 instanceof Integer) {
return compare((Integer) o1, (Integer) o2);
} else if (o1 instanceof Person) {
return compare((Person) o1, (Person) o2);
} else {
System.err.println("未找到适合的比较器");
return 1;
}
}
public int compare(String o1, String o2) {
int len1 = o1.length();
int len2 = o2.length();
int n = Math.min(len1, len2);
char v1[] = o1.toCharArray();
char v2[] = o2.toCharArray();
int pos = 0;
while (n-- != 0) {
char c1 = v1[pos];
char c2 = v2[pos];
if (c1 != c2) {
return c1 - c2;
}
pos++;
}
return len1 - len2;
}
public int compare(Integer o1, Integer o2) {
int val1 = o1.intValue();
int val2 = o2.intValue();
return (val1 < val2 ? -1 : (val1 == val2 ? 0 : 1));
}
public int compare(boolean o1, boolean o2) {
return (o1 == o2 ? 0 : (o1 == true ? 1: -1));
}
public int compare(Person o1, Person o2) {
String firstname1 = o1.getFirstName();
String firstname2 = o2.getFirstName();
String lastname1 = o1.getLastName();
String lastname2 = o2.getLastName();
boolean sex1 = o1.getSex();
boolean sex2 = o2.getSex();
int age1 = o1.getAge();
int age2 = o2.getAge();
return (compare(firstname1, firstname2) == 0 ?
(compare(lastname1, lastname2) == 0 ? (compare(sex1, sex2) == 0 ? (compare(age1, age2) == 0 ? 0 :
compare(age1, age2)) :
compare(sex1, sex2)) :
compare(lastname1, lastname2)) :
compare(firstname1, firstname2));
}
};
}
}
PersonTest.java
package com.founder.common;
public class PersonTest {
public static void main(String[] args) {
Person[] person = new Person[] {
new Person("ouyang", "feng", true, 25),
new Person("zhuang", "gw", false, 36),
new Person("zhuang", "gw", true, 36),
new Person("zhuang", "gw", true, 33),
new Person("zhuang", "gw", false, 23),
new Person("yang", "gw", true, 43)};
for (int i = 0; i < person.length; i++) {
System.out.println("before sort=" + person[i]);
}
java.util.Arrays.sort(person, Comparator.getComparator());
System.out.println("*************************************");
for (int i = 0; i < person.length; i++) {
System.out.println("after sort=" + person[i]);
}
}
}
输出结果为:
before sort=ouyang feng Male 25
before sort=zhuang gw Female 36
before sort=zhuang gw Male 36
before sort=zhuang gw Male 33
before sort=zhuang gw Female 23
before sort=yang gw Male 43
*************************************
after sort=ouyang feng Male 25
after sort=yang gw Male 43
after sort=zhuang gw Female 23
after sort=zhuang gw Female 36
after sort=zhuang gw Male 33
after sort=zhuang gw Male 36
posted on 2008-04-16 20:47
周锐 阅读(2767)
评论(5) 编辑 收藏 所属分类:
Java