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---------------------------------AJAX.html-------------------------------------------
<html>
 <head>
  <title>AJAX.html</title>
 </head>
 <script type="text/javascript">
 /*通过异步传输XMLHTTP发送参数到ajaxServlet,返回符合条件的XML文档*/
 function getResult(){
  var url = "ajaxServlet?action=send";
  if (window.XMLHttpRequest){
   req = new XMLHttpRequest();
  }else if (window.ActiveXObject)
  {
   req = new ActiveXObject("Microsoft.XMLHTTP");
  }
  if(req)
  {
   req.open("GET",url, true);
   req.onreadystatechange = complete;
   req.send(null);
  }
 }
 /*分析返回的XML文档*/
 function complete(){
  if (req.readyState == 4)
  {
   if (req.status == 200){
    var type = req.responseXML.getElementsByTagName("type_name");
    var str=new Array();
    for(var i=0;i<type.length;i++){
     str[i]=type[i].firstChild.data;
     document.all['td'].innerHTML+=str[i]+"<BR>";
    }
   }
  }
 }
</script>
 <body onLoad="getResult()">
  <table width="80%" border="0" cellspacing="0" cellpadding="0">
   <tr>
    <td id="td">
    </td>
   </tr>
  </table>
 </body>
</html>
---------------------------------ajaxServlet.java-----------------------------------------------------
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class ajaxServlet extends HttpServlet{
 private static final String CONTENT_TYPE = "text/xml; charset=gb2312";
 public void init() throws ServletException{}
 public void doGet(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException
 {
  response.setContentType(CONTENT_TYPE);
  PrintWriter out = response.getWriter();
  String action = request.getParameter("action");
  if (("send").equals(action))
  {
   StringBuffer sb = new StringBuffer("<type>");
   sb.append("<type_name>AA</type_name>");
   sb.append("<type_name>BB</type_name>");
   sb.append("<type_name>CC</type_name>");
   sb.append("<type_name>DD</type_name>");
   sb.append("</type>");
   out.write(sb.toString());
   out.close();
  }
 }
}
--------------------------------web.xml------------------------------------------------------
<?xml version = '1.0' encoding = 'UTF-8'?>
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
 <description>Empty web.xml file for Web Application</description>
 <servlet>
  <servlet-name>ajax</servlet-name>
  <servlet-class>ajaxServlet</servlet-class>
 </servlet>
    <servlet-mapping>
        <servlet-name>ajax</servlet-name>
        <url-pattern>/ajaxServlet</url-pattern>
    </servlet-mapping>
</web-app>

posted on 2006-08-29 14:06 保尔任 阅读(3757) 评论(2)  编辑  收藏

FeedBack:
# re: ajax简单实例(js内产生xmlHttpRequest,它和servlet交互返回xml显示在页面)[未登录]
2012-08-15 15:03 | 菜鸟
很好,如果用struts框架,怎么写struts.xml文件找到servlet呢  回复  更多评论
  
# re: ajax简单实例(js内产生xmlHttpRequest,它和servlet交互返回xml显示在页面)[未登录]
2015-01-13 11:53 | p
pp  回复  更多评论
  

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