呆呆向前冲的blog

  BlogJava :: 首页 :: 新随笔 :: 联系 :: 聚合  :: 管理 ::
  78 随笔 :: 43 文章 :: 5 评论 :: 74 Trackbacks

mmd 感觉脑子不够用了。还是用笨方法:一步一步写注释。

#include <stdio.h>
#include <stdlib.h> /* for atof() */
#include <ctype.h>

#define MAXOP 100       /* max size of operand and operator */
#define NUMBER '0'      /* signal that a number was found  */
#define MAXVAL 100      /* maxmium depth of value stack */
#define BUFSIZE 100

int getop(char []);
void push(double);
double pop(void);
int getch(void);
void ungetch(int);

int sp = 0;             /* next free stack position */
double val[MAXVAL];     /* value stack  */
char buf[BUFSIZE];      /* buffer for ungetch */
int bufp = 0;           /* next free position in buf */

/* reverse Polish Calculator */

main()
{
        int type;
        double op2;
        char s[MAXOP];

        while ((type = getop(s)) != EOF) {
                switch (type) {
                        case NUMBER:
                                push(atof(s));
                                break;
                        case '+':
                                push(pop() + pop());
                                break;
                        case '*':
                                push(pop() * pop());
                                break;
                        case '-':
                                op2 = pop();
                                push(pop() - op2);
                                break;
                        case '/':
                                op2 = pop();
                                if (op2 != 0.0)
                                        push(pop() / op2);
                                else
                                        printf("error: zero divisor\n");
                                break;
                        case '\n':
                                printf("\t%.8g\n",pop());
                                break;
                        default:
                                printf("error: unknown command %s\n",s);
                                break;
                }
        }
        return 0;
}
/* push: push f onto value stack  */
void push(double f)
{
        if (sp < MAXVAL)
                val[sp++] = f;
        else
                printf("error: stack full,can't push %g\n",f);
}
/* pop: pop and return top value from stack */
double pop(void)
{
        if (sp > 0)
                return val[--sp];
        else {
                printf("error: stack empty\n");
                return 0.0;
        }
}
/* getop: get next character or numeric oprand */
int getop(char s[])
{  
  //开始试图读取一个操作数或一个操作符
        int i,c;
  //忽略空格:直到读到非空字符
        while ((s[0] = c = getch()) == ' ' || c == '\t')
                ;
  //末尾加字符串结束标识
        s[1] = '\0';
        //if (!(s[0] == '-' && bufp == 1))
        //        if (!isdigit(c) && c != '.')
        //                return c;
  //如果读到的不是数字并且不是小数点,表示读到了一个操作符
        if (!isdigit(c) && c != '.')
                return c;       /* not a number */
        i = 0;
  //如果读到了数字,继续读取直到读到非数字字符
        if (isdigit(c)) /* collect integer part */
                while (isdigit(s[++i] = c = getch()))
                        ;
  //如果上面读取到的非数字字符是小数点,继续读取直到读取到非数字字符
        if (c == '.')   /* collect fraction part */
                while (isdigit(s[++i] = c = getch()))
                        ;
  //在s结尾前一位加结束标识
        s[i] = '\0';
  //如果未读到末尾,把最后读到的那个字符放到输入缓冲字符数组buf中
        if (c != EOF)
                ungetch(c);
        return NUMBER;
}

int getch(void)         /* get a (possibly pushed-back) character */
{
        return (bufp > 0) ? buf[--bufp] : getchar();
}

void ungetch(int c)     /* push character back on input */
{
        if (bufp >= BUFSIZE)
                printf("ungetch: too many characters\n");
        else
                buf[bufp++] = c;
}

posted on 2005-01-25 23:19 呆呆向前冲的blog 阅读(223) 评论(0)  编辑  收藏 所属分类: 爱好:网络编程

只有注册用户登录后才能发表评论。


网站导航: