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SELECT ename  
FROM scott.emp   
START WITH ename = 'KING'   
CONNECT BY PRIOR empno = mgr;   
 
--得到结果为:  
 
KING  
JONES  
SCOTT  
ADAMS  
FORD  
SMITH  
BLAKE  
ALLEN  
WARD  
MARTIN  
TURNER  
JAMES  
 
 
 
而:  
 
 
 
SELECT SYS_CONNECT_BY_PATH(ename, '>') "Path"   
FROM scott.emp   
START WITH ename = 'KING'   
CONNECT BY PRIOR empno = mgr;  
 
 
 
--得到结果为:  
 
 
 
>KING  
>KING>JONES  
>KING>JONES>SCOTT  
>KING>JONES>SCOTT>ADAMS  
>KING>JONES>FORD  
>KING>JONES>FORD>SMITH  
>KING>BLAKE  
>KING>BLAKE>ALLEN  
>KING>BLAKE>WARD  
>KING>BLAKE>MARTIN  
>KING>BLAKE>TURNER  
>KING>BLAKE>JAMES  
>KING>CLARK  
>KING>CLARK>MILLER 
SELECT ename
FROM scott.emp
START WITH ename = 'KING'
CONNECT BY PRIOR empno = mgr;

--得到结果为:

KING
JONES
SCOTT
ADAMS
FORD
SMITH
BLAKE
ALLEN
WARD
MARTIN
TURNER
JAMES

 

而:

 

SELECT SYS_CONNECT_BY_PATH(ename, '>') "Path"
FROM scott.emp
START WITH ename = 'KING'
CONNECT BY PRIOR empno = mgr;

 

--得到结果为:

 

>KING
>KING>JONES
>KING>JONES>SCOTT
>KING>JONES>SCOTT>ADAMS
>KING>JONES>FORD
>KING>JONES>FORD>SMITH
>KING>BLAKE
>KING>BLAKE>ALLEN
>KING>BLAKE>WARD
>KING>BLAKE>MARTIN
>KING>BLAKE>TURNER
>KING>BLAKE>JAMES
>KING>CLARK
>KING>CLARK>MILLER
 


其实SYS_CONNECT_BY_PATH这个函数是oracle9i才新提出来的!
它一定要和connect by子句合用!
第一个参数是形成树形式的字段,第二个参数是父级和其子级分隔显示用的分隔符!

START WITH 代表你要开始遍历的的节点!

CONNECT BY PRIOR 是标示父子关系的对应!

如下例子:

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select max(  
substr(  
sys_connect_by_path(column_name,',')  
,2)  
)  
from (select column_name,rownum rn from user_tab_columns where table_name ='AA_TEST')  
start with rn=1 connect by rn=rownum ; 
select max(
substr(
sys_connect_by_path(column_name,',')
,2)
)
from (select column_name,rownum rn from user_tab_columns where table_name ='AA_TEST')
start with rn=1 connect by rn=rownum ;

 

是将列用,进行分割成为一行,然后将首个,去掉,只取取最大的那个数据。

---------------------------------------------

下面是别人的例子:

1、带层次关系

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SQL> create table dept(deptno number,deptname varchar2(20),mgrno number);  
 
Table created.  
 
SQL> insert into dept values(1,'总公司',null);  
 
1 row created.  
 
SQL> insert into dept values(2,'浙江分公司',1);  
 
1 row created.  
 
SQL> insert into dept values(3,'杭州分公司',2);  
 
1 row created.  
 
SQL> commit;  
 
Commit complete.  
 
SQL> select max(substr(sys_connect_by_path(deptname,','),2)) from dept connect by prior deptno=mgrno;  
 
MAX(SUBSTR(SYS_CONNECT_BY_PATH(DEPTNAME,','),2))  
--------------------------------------------------------------------------------  
总公司,浙江分公司,杭州分公司 
SQL> create table dept(deptno number,deptname varchar2(20),mgrno number);

Table created.

SQL> insert into dept values(1,'总公司',null);

1 row created.

SQL> insert into dept values(2,'浙江分公司',1);

1 row created.

SQL> insert into dept values(3,'杭州分公司',2);

1 row created.

SQL> commit;

Commit complete.

SQL> select max(substr(sys_connect_by_path(deptname,','),2)) from dept connect by prior deptno=mgrno;

MAX(SUBSTR(SYS_CONNECT_BY_PATH(DEPTNAME,','),2))
--------------------------------------------------------------------------------
总公司,浙江分公司,杭州分公司

2、行列转换


如把一个表的所有列连成一行,用逗号分隔:

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SQL> select max(substr(sys_connect_by_path(column_name,','),2))  
from (select column_name,rownum rn from user_tab_columns where table_name ='DEPT')  
start with rn=1 connect by rn=rownum ;  
 
MAX(SUBSTR(SYS_CONNECT_BY_PATH(COLUMN_NAME,','),2))  
--------------------------------------------------------------------------------  
DEPTNO,DEPTNAME,MGRNO 

posted on 2011-08-05 11:03 xzc 阅读(1395) 评论(3)  编辑  收藏 所属分类: Oracle

评论:
# re: SYS_CONNECT_BY_PATH函数用法 ORACLE 2011-08-05 11:06 | xzc
SQL> select substr(max(sys_connect_by_path(attr_value, ',')), 2)
2 from (select attr_value, rownum rn
3 from attribute_value
4 where attr_id in
5 (select attr_id from attribute where attr_code = 'lan_id'))
6 start with rn = 1
7 connect by rn = rownum;

SUBSTR(MAX(SYS_CONNECT_BY_PATH
--------------------------------------------------------------------------------
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# re: SYS_CONNECT_BY_PATH函数用法 ORACLE 2011-08-05 11:09 | xzc
select max(substr(sys_connect_by_path(column_name, ','), 2))
from (select column_name, rownum rn
from user_tab_columns
where table_name = 'DEPT')
start with rn = 1
connect by rn = rownum;

select substr(max(sys_connect_by_path(attr_value, ',')), 2)
from (select attr_value, rownum rn
from attribute_value
where attr_id in
(select attr_id from attribute where attr_code = 'lan_id'))
start with rn = 1
connect by rn = rownum;  回复  更多评论
  
# re: SYS_CONNECT_BY_PATH函数用法 ORACLE 2012-07-12 21:22 | xzc
SQL> select wm_concat(lan_id) from rr_lan;

WM_CONCAT(LAN_ID)
--------------------------------------------------------------------------------
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